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duke knooby · 28 Oct 2007, 20:18

A light string ABCD has one end fixed at A, passes under a movable pulley of mass M at B, over a fixed pulley C and carries a mass M' at D. The parts of the string are vertical. Show M descends with acceleration g(M-2M')/M+4M'

g=9.8 m/s2

28 Oct 2007, 20:18	#1
duke knooby Mega Loafer Join Date: 24.06.2005 Location: belfast Posts: 17,909	A mathematical problem A light string ABCD has one end fixed at A, passes under a movable pulley of mass M at B, over a fixed pulley C and carries a mass M' at D. The parts of the string are vertical. Show M descends with acceleration g(M-2M')/M+4M' g=9.8 m/s2